A s-block element (M) reacts with oxygen to f | vedclass

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Question

(B) The reaction of alkali metals with excess oxygen leads to the formation of superoxides $(MO_{2})$.Potassium $(K)$,Rubidium $(Rb)$,and Cesium $(Cs)

Vedclass · Accepted Answer

$K$

Vedclass · Answer

(B) The reaction of alkali metals with excess oxygen leads to the formation of superoxides $(MO_{2})$.Potassium $(K)$,Rubidium $(Rb)$,and Cesium $(Cs)$ form superoxides ($KO_{2}$,$RbO_{2}$,$CsO_{2}$) which are paramagnetic due to the presence of one unpaired electron in the $\pi^* 2p$ molecular orbital of the superoxide ion $(O_{2}^{-})$.$KO_{2}$ is a pale yellow solid.Sodium $(Na)$ forms a peroxide $(Na_{2}O_{2})$,which is diamagnetic and white.Calcium $(Ca)$ and Magnesium $(Mg)$ form oxides ($CaO$,$MgO$) or peroxides $(CaO_{2})$,which are diamagnetic.Therefore,the element $(M)$ is $K$.

$A$ $s$-block element $(M)$ reacts with oxygen to form an oxide of the formula $MO_{2}$. The oxide is pale yellow in colour and paramagnetic. The element $(M)$ is:

Similar Questions

What is the product formed when sodium nitrate is heated at a temperature of ${800\,^o}C$?

What is obtained when sodium metal is heated in a stream of dry ammonia?

The correct statements are:
$I$. The low solubility of $LiF$ is due to its high lattice enthalpy.
$II$. $LiBr$ is soluble in acetone.
$III$. $LiCl$ is soluble in pyridine.
$IV$. The order of melting points of alkali metal halides is $MF > MCl > MBr > MI$.

Which of the following statements are correct regarding lithium $(Li)$ and magnesium $(Mg)$?
$I$) They react slowly with water
$II$) Their bicarbonates are solids
$III$) Their chlorides are not soluble in ethanol
$IV$) Their nitrates decompose easily on heating
The correct option is

$Ca + 2C$ $\rightarrow CaC_2$ $\xrightarrow{N_2, \Delta} A$
Compound $(A)$ is used as a/an:

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