A 17 , m long ladder leans on a wall such tha | vedclass

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(C) Let the length of the ladder be $L = 17 \, m$.Let the distance of the base of the ladder from the wall be $b = 8 \, m$.Let the height reached by t

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$15$

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(C) Let the length of the ladder be $L = 17 \, m$.Let the distance of the base of the ladder from the wall be $b = 8 \, m$.Let the height reached by the ladder on the wall be $h$.The wall,the ground,and the ladder form a right-angled triangle where the ladder is the hypotenuse.According to the Pythagorean theorem: $h^2 + b^2 = L^2$.Substituting the values: $h^2 + 8^2 = 17^2$.$h^2 + 64 = 289$.$h^2 = 289 - 64 = 225$.$h = \sqrt{225} = 15 \, m$.Thus,the upper end of the ladder reaches a height of $15 \, m$ on the wall.

$A$ $17 \, m$ long ladder leans on a wall such that its lower end rests $8 \, m$ away from the base of the wall. Then,its upper end reaches to the height of $\ldots \ldots \ldots \, m$ on the wall.

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