A 20, text{litre} mixture of milk and water c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The initial $20\, 	ext{litre}$ mixture contains milk and water in the ratio $3:2$. Thus,the amount of milk is $12\, 	ext{litres}$ and water is $

Vedclass · Accepted Answer

$9:1$

Vedclass · Answer

(B) The initial $20\, 	ext{litre}$ mixture contains milk and water in the ratio $3:2$. Thus,the amount of milk is $12\, 	ext{litres}$ and water is $8\, 	ext{litres}$.Step $1$: When $10\, 	ext{litres}$ of the mixture is removed,the amount of milk removed is $(3/5) 	imes 10 = 6\, 	ext{litres}$ and water removed is $(2/5) 	imes 10 = 4\, 	ext{litres}$. Remaining: $6\, 	ext{litres}$ milk and $4\, 	ext{litres}$ water. After adding $10\, 	ext{litres}$ of pure milk,the container has $6+10 = 16\, 	ext{litres}$ of milk and $4\, 	ext{litres}$ of water.Step $2$: When $10\, 	ext{litres}$ of this new mixture is removed,the ratio of milk to water is $16:4$,which is $4:1$. The amount of milk removed is $(4/5) 	imes 10 = 8\, 	ext{litres}$ and water removed is $(1/5) 	imes 10 = 2\, 	ext{litres}$. Remaining: $16-8 = 8\, 	ext{litres}$ milk and $4-2 = 2\, 	ext{litres}$ water. After adding $10\, 	ext{litres}$ of pure milk,the container has $8+10 = 18\, 	ext{litres}$ of milk and $2\, 	ext{litres}$ of water.The final ratio of milk to water is $18:2$,which simplifies to $9:1$.

Similar Questions

Two vessels $A$ and $B$ contain milk and water mixed in the ratio $8: 5$ and $5: 2,$ respectively. The ratio in which these two mixtures should be mixed to get a new mixture containing $69 \frac{3}{13} \%$ milk is

$A$ can contains a mixture of two liquids $A$ and $B$ in the ratio $4:7$. When $6 \text{ litres}$ of the mixture are drawn off and the can is filled with liquid $B$,the ratio of $A$ and $B$ becomes $3:7$. How many litres of liquid $A$ were contained in the can initially?

In what ratio should tea at ₹ $240$ per $kg$ be mixed with tea at ₹ $280$ per $kg$ so that on selling the mixture at ₹ $324$ per $kg$ there is a profit of $20 \%$?

$600 \, gm$ of sugar solution contains $40 \%$ sugar. How much sugar should be added to make the concentration $50 \%$ in the solution? (in $gm$)

Varun's expenditures and savings are in the ratio of $4:1$. His income increases by $20\%$. If his savings increase by $12\%$, by how much percentage should his expenditure increase?

Vedclass Test Series

Exam Paper Generator

Online Exam Module