A 44 ; mH inductor is connected to 220 ; V, 5 | vedclass

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(B) Given: Inductance $L = 44 \; mH = 44 	imes 10^{-3} \; H$,Voltage $V_{rms} = 220 \; V$,Frequency $f = 50 \; Hz$.The inductive reactance $X_L$ is g

Vedclass · Accepted Answer

$15.92$

Vedclass · Answer

(B) Given: Inductance $L = 44 \; mH = 44 	imes 10^{-3} \; H$,Voltage $V_{rms} = 220 \; V$,Frequency $f = 50 \; Hz$.The inductive reactance $X_L$ is given by the formula $X_L = \omega L = 2 \pi f L$.Substituting the values: $X_L = 2 	imes 3.1416 	imes 50 	imes 44 	imes 10^{-3} \; \Omega$.$X_L = 314.16 	imes 44 	imes 10^{-3} \; \Omega = 13.823 \; \Omega$.The $rms$ current $I_{rms}$ is calculated as $I_{rms} = \frac{V_{rms}}{X_L}$.$I_{rms} = \frac{220}{13.823} \approx 15.92 \; A$.Thus,the $rms$ value of the current is $15.92 \; A$.

$A$ $44 \; mH$ inductor is connected to $220 \; V, 50 \; Hz$ $ac$ supply. Determine the $rms$ value of the current (in $A$) in the circuit.

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