The propagation of an action potential during | vedclass

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Question

(D) During the conduction of a nerve impulse,the resting membrane potential is disturbed by a stimulus. This stimulus causes the voltage-gated $Na^+$

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$Na^+$ ions from extracellular fluid to intracellular fluid

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(D) During the conduction of a nerve impulse,the resting membrane potential is disturbed by a stimulus. This stimulus causes the voltage-gated $Na^+$ channels to open,leading to a rapid influx of $Na^+$ ions from the extracellular fluid $(ECF)$ into the intracellular fluid $(ICF)$. This process is known as depolarization,which generates the action potential. Therefore,the propagation of the action potential is primarily driven by the movement of $Na^+$ ions from the $ECF$ to the $ICF$.

The propagation of an action potential during nerve impulse conduction is made possible by the movement of:

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