AgF, AgCl, NaCl, NaBr, NaI are colourless but | vedclass

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Question

(A) According to Fajan's rule,the polarising power of a cation $(Ag^{+})$ is high. Due to the larger size and higher polarisability of $Br^{-}$ and $I

Vedclass · Accepted Answer

$Ag^{+}$ polarises $Br^{-}$ and $I^{-}$ and is not able to polarise $Cl^{-}$ and $F^{-}$

Vedclass · Answer

(A) According to Fajan's rule,the polarising power of a cation $(Ag^{+})$ is high. Due to the larger size and higher polarisability of $Br^{-}$ and $I^{-}$ ions compared to $F^{-}$ and $Cl^{-}$,the $Ag^{+}$ ion can effectively polarise the electron cloud of $Br^{-}$ and $I^{-}$. This polarisation leads to a decrease in the energy gap between the highest occupied molecular orbital and the lowest unoccupied molecular orbital,allowing for electronic transitions in the visible region,which results in the observed colour.

$AgF, AgCl, NaCl, NaBr, NaI$ are colourless but $AgBr$ and $AgI$ are coloured because

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