$3$ boys $B_i, i = 1, 2, 3$ and $6$ girls $G_i, i = 1, 2, . . . , 6$ are to be seated in a row. The number of ways they can be seated so that $B_1, B_2$ are separated and $G_1, G_2$ are also separated is equal to:
- A$5 \times 8!$
- B$44 \times 7!$
- C$46 \times 7!$
- D$40 \times 7!$
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