EAN of the central metal in the complexes K_2 | vedclass

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(C) The $EAN$ (Effective Atomic Number) is calculated as: $EAN = Z - 	ext{oxidation state} + 2 	imes (	ext{coordination number})$.$1$. For $K_2[Ni(

Vedclass · Accepted Answer

$34, 35, 86$

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(C) The $EAN$ (Effective Atomic Number) is calculated as: $EAN = Z - 	ext{oxidation state} + 2 	imes (	ext{coordination number})$.$1$. For $K_2[Ni(CN)_4]$: $Ni$ is in $+2$ oxidation state. $Z = 28$. $EAN = 28 - 2 + 2(4) = 26 + 8 = 34$.$2$. For $[Cu(NH_3)_4]SO_4$: $Cu$ is in $+2$ oxidation state. $Z = 29$. $EAN = 29 - 2 + 2(4) = 27 + 8 = 35$.$3$. For $K_2[PtCl_6]$: $Pt$ is in $+4$ oxidation state. $Z = 78$. $EAN = 78 - 4 + 2(6) = 74 + 12 = 86$.Thus,the values are $34, 35, 86$.

$EAN$ of the central metal in the complexes $K_2[Ni(CN)_4]$,$[Cu(NH_3)_4]SO_4$ and $K_2[PtCl_6]$ are respectively.

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