CH_2=CH-CH(OH)-CH_2-CH_2OH xrightarrow{MnO_2} | vedclass

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Question

(A) $MnO_2$ is a selective oxidizing agent that specifically oxidizes allylic and benzylic alcohols to their corresponding aldehydes or ketones,while

Vedclass · Accepted Answer

$CH_2=CH-C(=O)-CH_2-CH_2OH$

Vedclass · Answer

(A) $MnO_2$ is a selective oxidizing agent that specifically oxidizes allylic and benzylic alcohols to their corresponding aldehydes or ketones,while leaving saturated alcohols unaffected.In the given molecule,the secondary alcohol group at the third carbon is allylic $(CH_2=CH-CH(OH)-)$,whereas the primary alcohol group at the end is saturated.Therefore,only the allylic alcohol is oxidized to a ketone group $(C=O)$.$CH_2=CH-CH(OH)-CH_2-CH_2OH \xrightarrow{MnO_2} CH_2=CH-C(=O)-CH_2-CH_2OH$

$CH_2=CH-CH(OH)-CH_2-CH_2OH \xrightarrow{MnO_2} A$. $A$ is:

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