H_3PO_4 xrightarrow{250 ^oC} (X) xrightarrow{ | vedclass

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(C) The thermal decomposition of orthophosphoric acid $(H_3PO_4)$ occurs in stages.At $250\ ^oC$,$H_3PO_4$ loses water to form pyrophosphoric acid $(H

Vedclass · Accepted Answer

$(X) = 	ext{Pyrophosphoric acid (solid)}, (Y) = 	ext{Metaphosphoric acid (solid)}$

Vedclass · Answer

(C) The thermal decomposition of orthophosphoric acid $(H_3PO_4)$ occurs in stages.At $250\ ^oC$,$H_3PO_4$ loses water to form pyrophosphoric acid $(H_4P_2O_7)$,which is a solid: $2H_3PO_4 \xrightarrow{250\ ^oC} H_4P_2O_7 + H_2O$.At $600\ ^oC$,further heating leads to the formation of metaphosphoric acid $(HPO_3)$,which is a solid: $H_4P_2O_7 \xrightarrow{600\ ^oC} 2HPO_3 + H_2O$.Therefore,$(X)$ is pyrophosphoric acid (solid) and $(Y)$ is metaphosphoric acid (solid).

$H_3PO_4$ $\xrightarrow{250\ ^oC}$ $(X)$ $\xrightarrow{600\ ^oC}$ $(Y)$
$H_3PO_4$ $\xrightarrow{600\ ^oC}$ $(Y)$
$(X)$ and $(Y)$ are:

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$H_3PO_4$ $\xrightarrow{250\ ^oC}$ $(X)$ $\xrightarrow{600\ ^oC}$ $(Y)$$H_3PO_4$ $\xrightarrow{600\ ^oC}$ $(Y)$$(X)$ and $(Y)$ are: