Na + Al_2O_3 xrightarrow{text{High temperatur | vedclass

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Question

(C) The reaction of $Na$ with $Al_2O_3$ at high temperature produces sodium oxide $(Na_2O)$ and aluminum metal: $6Na + Al_2O_3 \rightarrow 3Na_2O + 2A

Vedclass · Accepted Answer

$Na_2CO_3$

Vedclass · Answer

(C) The reaction of $Na$ with $Al_2O_3$ at high temperature produces sodium oxide $(Na_2O)$ and aluminum metal: $6Na + Al_2O_3 \rightarrow 3Na_2O + 2Al$.When $Na_2O$ reacts with $CO_2$ in the presence of water,it forms sodium carbonate $(Na_2CO_3)$: $Na_2O + CO_2 \rightarrow Na_2CO_3$.Thus,$X$ is $Na_2O$ and $Y$ is $Na_2CO_3$.Therefore,option $C$ is correct.

Metals	Ore
$1$. Barium	$d$. Witherite
$2$. Magnesium	$a$. Carnallite
$3$. Potassium	$b$. Sylvine
$4$. Strontium	$c$. Celestine

$Na + Al_2O_3$ $\xrightarrow{\text{High temperature}} X$ $\xrightarrow[\text{water}]{CO_2} Y$; compound $Y$ is

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