The average speed (U_{avg}) of O_2 at pi time | vedclass

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Question

(C) The formula for average speed is $U_{avg} = \sqrt{\frac{8RT}{\pi M}}$.Using the ideal gas equation $PV = nRT$,we can substitute $RT = \frac{PV}{n}

Vedclass · Accepted Answer

$10^3 \ m/s$

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(C) The formula for average speed is $U_{avg} = \sqrt{\frac{8RT}{\pi M}}$.Using the ideal gas equation $PV = nRT$,we can substitute $RT = \frac{PV}{n}$.Thus,$U_{avg} = \sqrt{\frac{8PV}{\pi Mn}}$.Given: $P = \pi 	imes 10 \ bar = \pi 	imes 10^6 \ Pa$,$V = 8 \ L = 8 	imes 10^{-3} \ m^3$,$n = 2 \ mol$,$M = 32 \ g/mol = 32 	imes 10^{-3} \ kg/mol$.Substituting the values: $U_{avg} = \sqrt{\frac{8 	imes (\pi 	imes 10^6) 	imes (8 	imes 10^{-3})}{\pi 	imes (32 	imes 10^{-3}) 	imes 2}}$.$U_{avg} = \sqrt{\frac{64 	imes 10^3}{64 	imes 10^{-3}}} = \sqrt{10^6} = 10^3 \ m/s$.

The average speed $(U_{avg})$ of $O_2$ at $\pi \times 10 \ bar$ pressure in an $8 \ L$ container containing $2 \ moles$ is:

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