[FeF_6]^{3-} has ........ hybridisation and . | vedclass

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(B) The electronic configuration of $Fe$ is $[Ar] 3d^6 4s^2$. In the complex $[FeF_6]^{3-}$,the oxidation state of $Fe$ is $+3$,resulting in an electr

Vedclass · Accepted Answer

$sp^3d^2$,octahedral

Vedclass · Answer

(B) The electronic configuration of $Fe$ is $[Ar] 3d^6 4s^2$. In the complex $[FeF_6]^{3-}$,the oxidation state of $Fe$ is $+3$,resulting in an electronic configuration of $[Ar] 3d^5$. Since $F^-$ is a weak field ligand,it does not cause pairing of electrons in the $3d$ orbitals. Therefore,the $4s$,$4p$,and $4d$ orbitals participate in hybridization,resulting in $sp^3d^2$ hybridization. This hybridization corresponds to an octahedral geometry. Hence,option $B$ is the correct answer.

$A. sp^3$	$(i). [Co(NH_3)_6]^{3+}$
$B. dsp^2$	$(ii). [Ni(CO)_4]$
$C. sp^3d^2$	$(iii). [Pt(NH_3)_2Cl_2]$
$D. d^2sp^3$	$(iv). [CoF_6]^{3-}$
	$(v). [Fe(CO)_5]$

$[FeF_6]^{3-}$ has ........ hybridisation and ....... geometry. Select the best option to fill the blank space respectively:

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$A. sp^3$ $(i). [Co(NH_3)_6]^{3+}$
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$C. sp^3d^2$ $(iii). [Pt(NH_3)_2Cl_2]$
$D. d^2sp^3$ $(iv). [CoF_6]^{3-}$
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