$3 \text{ mole}$ of a mixture of $FeSO_4$ and $Fe_2(SO_4)_3$ required $100 \text{ mL}$ of $2 \text{ M}$ $KMnO_4$ solution in acidic medium. Hence,the mole fraction of $FeSO_4$ in the mixture is:

  • A
    $\frac{3}{5}$
  • B
    $\frac{2}{3}$
  • C
    $\frac{2}{5}$
  • D
    $\frac{1}{3}$

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