29.5 mg of an organic compound containing ni | vedclass

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(C) Moles of $HCl$ taken $= 20 	imes 0.1 	imes 10^{-3} = 2 	imes 10^{-3} \ mol$. Moles of $HCl$ neutralized by $NaOH$ solution $= 15 	imes 0.1 	i

Vedclass · Accepted Answer

$23.7$

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(C) Moles of $HCl$ taken $= 20 	imes 0.1 	imes 10^{-3} = 2 	imes 10^{-3} \ mol$. Moles of $HCl$ neutralized by $NaOH$ solution $= 15 	imes 0.1 	imes 10^{-3} = 1.5 	imes 10^{-3} \ mol$. Moles of $HCl$ neutralized by ammonia $= 2 	imes 10^{-3} - 1.5 	imes 10^{-3} = 0.5 	imes 10^{-3} \ mol$. Since $1 \ mol$ of $NH_3$ reacts with $1 \ mol$ of $HCl$,moles of $N = 0.5 	imes 10^{-3} \ mol$. Mass of nitrogen $= 0.5 	imes 10^{-3} \ mol 	imes 14 \ g/mol = 7 	imes 10^{-3} \ g = 7 \ mg$. Percentage of nitrogen $= (	ext{Mass of nitrogen} / 	ext{Mass of compound}) 	imes 100 = (7 \ mg / 29.5 \ mg) 	imes 100 \approx 23.7 \%$.

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