(C) Impulse $J$ is defined as the product of the average force $F$ and the time interval $\Delta t$ for which the force acts: $J = F \cdot \Delta t$.I

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(C) Impulse $J$ is defined as the product of the average force $F$ and the time interval $\Delta t$ for which the force acts: $J = F \cdot \Delta t$.In the first case,the impulse is $J = F \cdot \Delta t$.In the second case,the force $F$ remains the same,but the contact time is doubled,i.e.,$\Delta t' = 2 \Delta t$.Therefore,the new impulse $J'$ is given by $J' = F \cdot (2 \Delta t) = 2(F \cdot \Delta t) = 2J$.Thus,the new impulse is twice the original impulse.

Class 11 Physics Newton's Laws of Motion and Friction Third Law of Motion and Momentum and Impulse

Medium

$A$ boy hits a baseball with a bat and imparts an impulse $J$ to the ball. The boy hits the ball again with the same force,except that the ball and the bat are in contact for twice the amount of time as in the first hit. The new impulse equals:

A
half the original impulse
B
the original impulse
C
twice the original impulse
D
four times the original impulse

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Chapter

Newton's Laws of Motion and Friction

Subtopic

Third Law of Motion and Momentum and Impulse

$A$ player catches a cricket ball of mass $150 \, g$ moving at a speed of $20 \, m/s$. If the catching process is completed in $0.1 \, s$,the force of the blow exerted by the ball on the hands of the player is ........... $N$.

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$A$ force of $10 \, N$ acts on a body of mass $20 \, kg$ for $10 \, s$. The change in its momentum is ........... $kg \cdot m/s$.

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$A$ cricket ball of mass $250\, g$ collides with a bat with velocity $10\, m/s$ and returns with the same velocity within $0.01\, s$. The force exerted on the ball is ....... $N$.

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$A$ ball of mass $0.5 \ kg$ is dropped from a height of $40 \ m$. The ball hits the ground and rises to a height of $10 \ m$. The impulse imparted to the ball during its collision with the ground is (Take $g = 9.8 \ m/s^2$)

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$A$ machine gun fires a bullet of mass $40\,g$ with a velocity $1200\,m/s$. The man holding it can exert a maximum force of $144\,N$ on the gun. How many bullets can he fire per second at the most?

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$A$ boy hits a baseball with a bat and imparts an impulse $J$ to the ball. The boy hits the ball again with the same force,except that the ball and the bat are in contact for twice the amount of time as in the first hit. The new impulse equals:

Similar Questions

$A$ player catches a cricket ball of mass $150 \, g$ moving at a speed of $20 \, m/s$. If the catching process is completed in $0.1 \, s$,the force of the blow exerted by the ball on the hands of the player is ........... $N$.

$A$ force of $10 \, N$ acts on a body of mass $20 \, kg$ for $10 \, s$. The change in its momentum is ........... $kg \cdot m/s$.

$A$ cricket ball of mass $250\, g$ collides with a bat with velocity $10\, m/s$ and returns with the same velocity within $0.01\, s$. The force exerted on the ball is ....... $N$.

$A$ ball of mass $0.5 \ kg$ is dropped from a height of $40 \ m$. The ball hits the ground and rises to a height of $10 \ m$. The impulse imparted to the ball during its collision with the ground is (Take $g = 9.8 \ m/s^2$)

$A$ machine gun fires a bullet of mass $40\,g$ with a velocity $1200\,m/s$. The man holding it can exert a maximum force of $144\,N$ on the gun. How many bullets can he fire per second at the most?

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