A circuit element is placed in a closed box. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) From the graph,the potential difference $V$ as a function of time $t$ is a linear equation: $V(t) = mt + c$.At $t=0$,$V=2\, V$,so the intercept $c

Vedclass · Accepted Answer

capacitance of $0.5\, F$

Vedclass · Answer

(D) From the graph,the potential difference $V$ as a function of time $t$ is a linear equation: $V(t) = mt + c$.At $t=0$,$V=2\, V$,so the intercept $c=2$.At $t=3\, s$,$V=8\, V$,so the slope $m = \frac{8-2}{3-0} = \frac{6}{3} = 2\, V/s$.Thus,$V(t) = 2t + 2$.For a capacitor,$V = \frac{q}{C} = \frac{1}{C} \int i \, dt$.Given $i = 1\, A$,we have $V = \frac{1}{C} \int 1 \, dt = \frac{t}{C} + V_0$,where $V_0$ is the initial voltage at $t=0$.Comparing $V(t) = \frac{1}{C}t + 2$ with $V(t) = 2t + 2$,we get $\frac{1}{C} = 2$,which implies $C = 0.5\, F$.

$A$ circuit element is placed in a closed box. At time $t=0$,a constant current generator supplying a current of $1\, A$ is connected across the box. The potential difference across the box varies according to the graph shown in the figure. The element in the box is:

Similar Questions

How much time does it take for the current to decay to half of its initial value in the following charging circuit?

$A$ capacitor is a perfect insulator for

$A$ parallel plate capacitor is charged to a potential difference of $50 \, V$. It is discharged through a resistance. After $1 \, s$,the potential difference between the plates becomes $40 \, V$. Then:

The potential difference between the plates of a parallel plate capacitor is changing at the rate of $10^6\, V/s$. If the capacitance is $2\,\mu F$,the displacement current in the dielectric of the capacitor will be......$A$

The figure shows an experimental plot for discharging of a capacitor in an $R-C$ circuit. The time constant $\tau$ of this circuit lies between

Vedclass Test Series

Exam Paper Generator

Online Exam Module