A bar magnet is moved along the axis of a cop | vedclass

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(D) According to Lenz's law,the induced current in the ring will create a magnetic field that opposes the change in magnetic flux.When viewed from the

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Both $(B)$ and $(C)$.

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(D) According to Lenz's law,the induced current in the ring will create a magnetic field that opposes the change in magnetic flux.When viewed from the side of the magnet,an anticlockwise current in the ring corresponds to a magnetic North pole $(N)$ facing the magnet.Case $1$: If the North pole of the magnet faces the ring and moves towards it,the ring will induce a North pole to repel it,resulting in an anticlockwise current.Case $2$: If the South pole of the magnet faces the ring and moves away from it,the ring will induce a North pole to attract it,also resulting in an anticlockwise current.Therefore,both $(B)$ and $(C)$ are correct.

$A$ bar magnet is moved along the axis of a copper ring placed far away from the magnet. Looking from the side of the magnet,an anticlockwise current is found to be induced in the ring. Which of the following may be true?

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There are two square loops $A$ and $B$. When $A$ moves towards $B$,a current starts flowing in $B$ as shown in the figure,and the current in $B$ stops when $A$ stops moving. From this,we can infer that (Assume loop $B$ is at rest):

Assertion $(A):$ The bar magnet falling vertically along the axis of the horizontal coil will have an acceleration less than $g$.
Reason $(R):$ Clockwise current is induced in the coil.

Assertion : An induced current has a direction such that the magnetic field due to the current opposes the change in the magnetic flux that induces the current.
Reason : The above statement is in accordance with the conservation of energy.

The working of a dynamo is based on the principle of

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