2,3-Dimethyl-2-butene can be prepared by heat | vedclass

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Question

(A) $3,3-$Dimethyl$-1-$butene $(CH_3-C(CH_3)_2-CH=CH_2)$ on treatment with a strong acid undergoes protonation to form a secondary carbocation: $CH_3-

Vedclass · Accepted Answer

$CH_3-C(CH_3)_2-CH=CH_2$

Vedclass · Answer

(A) $3,3-$Dimethyl$-1-$butene $(CH_3-C(CH_3)_2-CH=CH_2)$ on treatment with a strong acid undergoes protonation to form a secondary carbocation: $CH_3-C(CH_3)_2-C^+H-CH_3$. This carbocation undergoes a $1,2-$methyl shift to form a more stable tertiary carbocation: $CH_3-C^+(CH_3)-CH(CH_3)-CH_3$. Finally,it loses a proton (deprotonation) to form the more substituted alkene,$2,3-$dimethyl$-2-$butene $(CH_3-C(CH_3)=C(CH_3)-CH_3)$,as the major product.

$2,3-$Dimethyl$-2-$butene can be prepared by heating which of the following compounds with a strong acid?

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