$A$ solid cylinder of diameter $30 \ cm$ is rolled down an inclined plane from a height of $2 \ m$. If there is no energy loss due to friction,the angular velocity at the base of the plane is ....... $rad/s$. (Take $g = 10 \ m/s^2$)

  • A
    $68$
  • B
    $8.5$
  • C
    $17$
  • D
    $34$

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Similar Questions

$A$ rigid body of mass $M$ and radius $R$ rolls without slipping on an inclined plane of inclination $\theta$,under gravity. Match the type of body in Column-$I$ with the magnitude of the force of friction in Column-$II$.
Column-$I$ Column-$II$
$(A)$ Ring $(I)$ $\frac{Mg \sin \theta}{3.5}$
$(B)$ Solid sphere $(II)$ $\frac{Mg \sin \theta}{2}$
$(C)$ Solid cylinder $(III)$ $\frac{Mg \sin \theta}{3}$
$(D)$ Hollow cylinder $(IV)$ $\frac{Mg \sin \theta}{2.5}$

Which of the following is true about the angular momentum of a cylinder rolling down a slope without slipping?

An object is rolling on an inclined plane. Its linear and rotational kinetic energies are equal. The object is:

$A$ solid sphere rolls down without slipping on an inclined plane,then the percentage of rotational kinetic energy of the total energy will be ........ $\%.$

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$A$ uniform solid spherical ball is rolling down a smooth inclined plane from a height $h$. The velocity attained by the ball when it reaches the bottom of the inclined plane is $v$. If the ball is now thrown vertically upwards with the same velocity $v$,the maximum height to which the ball will rise is

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