$A$ motor shaft rotates at a constant angular velocity of $3000$ revolutions per minute. Through what angle (in radians) will it rotate in $1$ second?

The acceleration vector of a particle in uniform circular motion averaged over one complete cycle is a null vector. This statement is:

The angular speed of the seconds needle in a mechanical watch is:

As shown in the figure,a particle is moving with a constant speed $v = \pi \, m/s$ in a circular path. Considering its motion from point $A$ to point $B$,where the angle subtended at the center is $120^{\circ}$,the magnitude of the average velocity is:

$A$ particle $P$ is moving in a circle of radius $a$ with a uniform speed $u$. $C$ is the centre of the circle and $AB$ is the diameter. The angular velocity of $P$ about $A$ and $C$ are in the ratio:

When a particle moves in a uniform circular motion,it has: