If $\frac{2x + 3}{(x + 1)(x - 3)} = \frac{a}{x + 1} + \frac{b}{x - 3}$,then the value of $a + b$ is:

  • A
    $1$
  • B
    $2$
  • C
    $\frac{9}{4}$
  • D
    $\frac{-1}{4}$

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