1 , mg of gold undergoes decay with a 2.7 , t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The formula for radioactive decay is given by $N = N_0 \left( \frac{1}{2} \right)^n$, where $n = \frac{t}{T_{1/2}}$.Given:Initial amount $N_0 = 1

Vedclass · Accepted Answer

$0.125$

Vedclass · Answer

(D) The formula for radioactive decay is given by $N = N_0 \left( \frac{1}{2} ight)^n$, where $n = \frac{t}{T_{1/2}}$.Given:Initial amount $N_0 = 1 \, mg$Total time $t = 8.1 \, 	ext{days}$Half-life $T_{1/2} = 2.7 \, 	ext{days}$First, calculate the number of half-lives $n$:$n = \frac{8.1}{2.7} = 3$Now, substitute the values into the decay formula:$N = 1 	imes \left( \frac{1}{2} ight)^3$$N = \frac{1}{8} = 0.125 \, mg$Thus, the amount left after $8.1 \, 	ext{days}$ is $0.125 \, mg$.

$1 \, mg$ of gold undergoes decay with a $2.7 \, \text{days}$ half-life period. The amount left after $8.1 \, \text{days}$ is ......... $mg$.

Similar Questions

If the half-life of a radioactive sample is $10\, hours$,its mean life is .......... $hours$.

$A$ sample has a half-life of $10^{33}$ years. If the initial number of nuclei of the sample is $26 \times 10^{24}$,then the number of nuclei decayed in $1$ year is ........... $\times 10^{-7}$.

$A$ radioactive sample has a half-life of $5$ years. The percentage of the fraction decayed in $10$ years will be (in $\%$)

The half-life of $Au^{198}$ is $2.7 \, days$. The activity of $1.50 \, mg$ of $Au^{198}$ if its atomic weight is $198 \, g \, mol^{-1}$ is ....... $Ci$ $(N_A = 6 \times 10^{23} \, mol^{-1})$.

Define the $SI$ unit of radioactivity.

Vedclass Test Series

Exam Paper Generator

Online Exam Module