$1 \text{ Curie}$ is equal to
- A$3 \times 10^{10} \text{ disintegrations/sec}$
- B$3.7 \times 10^7 \text{ disintegrations/sec}$
- C$5 \times 10^7 \text{ disintegrations/sec}$
- D$3.7 \times 10^{10} \text{ disintegrations/sec}$
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