{g_e} and {g_p} denote the acceleration due t | vedclass

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Question

(b) $g \propto \frac{M}{{{R^2}}}$. If mass and radius of the planet are twice then ${g_\rho }$ will be half that of ${g_e}$ i.e. ${g_p} = \frac{{{g_e}

Vedclass · Accepted Answer

${g_p} = {g_e}/2$

Vedclass · Answer

(b) $g \propto \frac{M}{{{R^2}}}$. If mass and radius of the planet are twice then ${g_\rho }$ will be half that of ${g_e}$ i.e. ${g_p} = \frac{{{g_e}}}{2}$

${g_e}$ and ${g_p}$ denote the acceleration due to gravity on the surface of the earth and another planet whose mass and radius are twice as that of earth. Then

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