(B) The molar mass of $NaOH$ is $40 \, g/mol$.The number of moles of $NaOH$ is $n = \frac{40 \times 10^{-3} \, g}{40 \, g/mol} = 10^{-3} \, mol$.The c

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(B) The molar mass of $NaOH$ is $40 \, g/mol$.The number of moles of $NaOH$ is $n = \frac{40 \times 10^{-3} \, g}{40 \, g/mol} = 10^{-3} \, mol$.The concentration of $NaOH$ in $10 \, L$ is $[OH^-] = \frac{10^{-3} \, mol}{10 \, L} = 10^{-4} \, M$.$pOH = -\log_{10}[OH^-] = -\log_{10}(10^{-4}) = 4$.Using the relation $pH + pOH = 14$,we get $pH = 14 - 4 = 10$.

Class 11 Chemistry 6-2.Equilibrium-II (Ionic Equilibrium)pH of strong Acids and strong Bases

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$40 \, mg$ of pure sodium hydroxide is dissolved in $10 \, L$ of distilled water. The $pH$ of the solution is

A
$9$
B
$10$
C
$11$
D
$12$

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6-2.Equilibrium-II (Ionic Equilibrium)

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pH of strong Acids and strong Bases

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$40 \ mg$ of pure sodium hydroxide is dissolved in $10 \ L$ of distilled water. The $p^H$ of the solution is ..........

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Which of the following solutions has the highest $pH = 14$?

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The $pH$ of a $10^{-10} \ M$ $HCl$ solution is approximately

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$40 \, mg$ of pure sodium hydroxide is dissolved in $10 \, L$ of distilled water. The $pH$ of the solution is

Similar Questions

The concentration of an aqueous $HCl$ solution is $10^{-9} \ N$. What is the $pH$ of the solution?

What is the $pH$ of a solution obtained by dissolving $0.2 \, g$ of $NaOH$ in $100 \, mL$ of water (in $.699$)?

$40 \ mg$ of pure sodium hydroxide is dissolved in $10 \ L$ of distilled water. The $p^H$ of the solution is ..........

Which of the following solutions has the highest $pH = 14$?

The $pH$ of a $10^{-10} \ M$ $HCl$ solution is approximately

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