$200\, MeV$ of energy may be obtained per fission of ${U^{235}}$. $A$ reactor is generating $1000\, kW$ of power. The rate of nuclear fission in the reactor is

  • A
    $1000$
  • B
    $2 \times 10^8$
  • C
    $3.125 \times 10^{16}$
  • D
    $931$

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Similar Questions

The scientific principle that forms the basis of the Tokamak technology is

What is the amount of $U^{235}$ in $kg$ consumed per hour in a nuclear reactor of $100 \, kW$ capacity? (Given $E_s = 200 \, MeV/fission$)

$A$ heavy nucleus $N$,at rest,undergoes fission $N \rightarrow P+Q$,where $P$ and $Q$ are two lighter nuclei. Let $\delta=M_N-M_P-M_Q$,where $M_P, M_Q$ and $M_N$ are the masses of $P, Q$ and $N$,respectively. $E_P$ and $E_Q$ are the kinetic energies of $P$ and $Q$,respectively. The speeds of $P$ and $Q$ are $v_P$ and $v_Q$,respectively. If $c$ is the speed of light,which of the following statement$(s)$ is(are) correct?
$(A)$ $E_P+E_Q=c^2 \delta$
$(B)$ $E_P=\left(\frac{M_P}{M_P+M_Q}\right) c^2 \delta$
$(C)$ $\frac{v_P}{v_Q}=\frac{M_Q}{M_P}$
$(D)$ The magnitude of momentum for $P$ as well as $Q$ is $c \sqrt{2 \mu \delta}$,where $\mu=\frac{M_P M_Q}{M_P+M_Q}$

The binding energies of nuclei $X$ and $Y$ are $E_1$ and $E_2$ respectively. Two atoms of $X$ fuse to give one atom of $Y$ and an energy $Q$ is released. Then:

If $200 \, MeV$ energy is released in the fission of a single ${U^{235}}$ nucleus, the number of fissions required per second to produce $1 \, kW$ power shall be (Given $1 \, eV = 1.6 \times 10^{-19} \, J$)

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