The dissociation constants $(K_a)$ of four acids are given below. Which of these is the strongest acid?
- A$2 \times 10^{-2}$
- B$0.02 \times 10^{-1}$
- C$3 \times 10^{-4}$
- D$2 \times 10^{-4}$
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Similar Questions
The order of decreasing basic strength of halides is:
Medium
View SolutionIdentify the conjugate acid-base pair respectively from the following equilibrium reaction.
$HPO_{4(aq)}^{2-} + H_2O_{(\ell)} \rightleftharpoons PO_{4(aq)}^{3-} + H_3O_{(aq)}^{+}$
$HPO_{4(aq)}^{2-} + H_2O_{(\ell)} \rightleftharpoons PO_{4(aq)}^{3-} + H_3O_{(aq)}^{+}$
Match the following acids in List-$I$ with their respective acid dissociation constants $(K_a)$ in List-$II$:
List-$I$ (Acid) List-$II$ $(K_a)$ $A$. Phenol $I$. $1 \times 10^{-13}$ $B$. Benzoic acid $II$. $3.0 \times 10^{-8}$ $C$. $HClO$ $III$. $1.0 \times 10^{-10}$ $D$. $CH_3COOH$ $IV$. $6.5 \times 10^{-5}$ $V$. $1.75 \times 10^{-5}$
The correct match is:
| List-$I$ (Acid) | List-$II$ $(K_a)$ |
|---|---|
| $A$. Phenol | $I$. $1 \times 10^{-13}$ |
| $B$. Benzoic acid | $II$. $3.0 \times 10^{-8}$ |
| $C$. $HClO$ | $III$. $1.0 \times 10^{-10}$ |
| $D$. $CH_3COOH$ | $IV$. $6.5 \times 10^{-5}$ |
| $V$. $1.75 \times 10^{-5}$ |
The correct match is:
Select the reaction which will be favoured in the forward direction.
Difficult
View SolutionThe conjugate base of $H_3O^{+}$ is
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