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(A) The given reaction is a haloform reaction followed by decarboxylation. Step $1$: Treatment with $I_2 + NaOH$ (iodoform test) converts the acetyl g

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(A) The given reaction is a haloform reaction followed by decarboxylation. Step $1$: Treatment with $I_2 + NaOH$ (iodoform test) converts the acetyl group $(-COCH_3)$ into a carboxylate group $(-COO^-)$ and produces $CHI_3$ (iodoform). Step $2$: Acidification $(H^+)$ gives the corresponding $\beta$-keto acid. Step $3$: Heating the $\beta$-keto acid causes decarboxylation (loss of $CO_2$) to yield cyclohexanone as the final product.

List-$I$	List-$II$
$A$. Grignard reagent	$1$. $H_2 / Pd-BaSO_4$
$B$. Clemmensen reduction	$2$. $N_2H_4 / KOH / (CH_2OH)_2$
$C$. Rosenmund reduction	$3$. $CH_3MgX$
$D$. Wolff-Kishner reduction	$4$. $Zn-Hg / \text{conc. } HCl$
	$5$. $H_2 / Ni$

What will be the final product of the following reaction?

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Arrange the following compounds in decreasing order of reactivity towards nucleophilic addition reactions:
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Match the following lists:
List-$I$ List-$II$
$A$. Grignard reagent $1$. $H_2 / Pd-BaSO_4$
$B$. Clemmensen reduction $2$. $N_2H_4 / KOH / (CH_2OH)_2$
$C$. Rosenmund reduction $3$. $CH_3MgX$
$D$. Wolff-Kishner reduction $4$. $Zn-Hg / \text{conc. } HCl$
$5$. $H_2 / Ni$

For making a distinction between $2$-pentanone and $3$-pentanone,the reagent to be employed is

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