What will be the product $S$ in the following reaction?
$CH_3COOH$ $\xrightarrow{SOCl_2} P$ $\xrightarrow[Anhyd. AlCl_3]{Benzene} Q$ $\xrightarrow{HCN} R$ $\xrightarrow{HOH} S$
$CH_3COOH$ $\xrightarrow{SOCl_2} P$ $\xrightarrow[Anhyd. AlCl_3]{Benzene} Q$ $\xrightarrow{HCN} R$ $\xrightarrow{HOH} S$
- A$2-$hydroxy$-2-$phenylpropanoic acid
- B$3-$hydroxy$-3-$phenylbutanoic acid
- C$2-$hydroxy$-2-$phenylbutanenitrile
- D$2-$hydroxy$-2-$phenylpropanenitrile
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