Compound 'X' (molecular formula C_3H_8O) reac | vedclass

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Question

(A) Since product '$Y$' gives a silver mirror test,it must be an aldehyde. '$Y$' is formed by the oxidation of '$X$',which indicates that '$X$' is a p

Vedclass · Accepted Answer

$CH_3CH_2CH=NNHCONH_2$

Vedclass · Answer

(A) Since product '$Y$' gives a silver mirror test,it must be an aldehyde. '$Y$' is formed by the oxidation of '$X$',which indicates that '$X$' is a primary alcohol $(CH_3CH_2CH_2OH)$.$CH_3CH_2CH_2OH (X) \xrightarrow{K_2Cr_2O_7 + H_2SO_4} CH_3CH_2CHO (Y)$When '$Y$' $(CH_3CH_2CHO)$ reacts with semicarbazide $(NH_2CONHNH_2)$ in the presence of sodium acetate,it forms a semicarbazone derivative.$CH_3CH_2CHO + NH_2CONHNH_2 \rightarrow CH_3CH_2CH=NNHCONH_2 + H_2O$The product '$Z$' is $CH_3CH_2CH=NNHCONH_2$.

Compound '$X$' (molecular formula $C_3H_8O$) reacts with acidic potassium dichromate to give product '$Y$' (molecular formula $C_3H_6O$). '$Y$' gives a silver mirror test. When '$Y$' is reacted with aqueous $NH_2CONHNH_2$ and sodium acetate,it gives product '$Z$'. What is the structure of '$Z$'?

Similar Questions

The major product of the following reaction is

Identify $X, Y, Z$ in the following reaction sequence:

Which among the following compounds give a yellow solid when reacted with $NaOI/NaOH$? Choose the correct answer from the options given below $:$
$(A)$ $CH_3-CH(OH)-C_2H_5$
$(B)$ $CH_3-CH_2-CH_2-OH$
$(C)$ $CH_3-CO-C_2H_5$
$(D)$ $CH_3-COOH$
$(E)$ $CH_3-CH_2-CHO$

The major product formed in the following reaction is:

In the following reaction:
$\text{Carbonyl compound} + MeOH \xleftarrow[HCl]{} \text{acetal}$
The rate of the reaction is the highest for:

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