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(A) This reaction is a crossed Cannizzaro reaction.In a crossed Cannizzaro reaction involving formaldehyde $(HCHO)$ and another aldehyde (like benzald

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Benzyl alcohol and sodium formate

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(A) This reaction is a crossed Cannizzaro reaction.In a crossed Cannizzaro reaction involving formaldehyde $(HCHO)$ and another aldehyde (like benzaldehyde,$C_6H_5CHO$),formaldehyde is more reactive towards nucleophilic attack by $OH^-$.Therefore,formaldehyde undergoes oxidation to form a formate ion $(HCOO^-)$,which forms sodium formate $(HCOONa)$ in the presence of $NaOH$.The other aldehyde (benzaldehyde) undergoes reduction to form the corresponding alcohol,which is benzyl alcohol $(C_6H_5CH_2OH)$.The overall reaction is: $C_6H_5CHO + HCHO + NaOH \rightarrow C_6H_5CH_2OH + HCOONa$.

What are the products formed when a mixture of benzaldehyde and formaldehyde is heated with an aqueous solution of $NaOH$?

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