What is the product obtained when m-chloroben | vedclass

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(C) $m$-Chlorobenzaldehyde does not have any $\alpha$-hydrogen atoms. Therefore,it undergoes the Cannizzaro reaction when treated with a concentrated

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$C$

Vedclass · Answer

(C) $m$-Chlorobenzaldehyde does not have any $\alpha$-hydrogen atoms. Therefore,it undergoes the Cannizzaro reaction when treated with a concentrated base like $50\% KOH$. In this reaction,one molecule of the aldehyde is oxidized to a carboxylate ion ($m$-chlorobenzoate),and another molecule is reduced to an alcohol ($m$-chlorobenzyl alcohol). The correct product is shown in option $C$.

List-$I$ Reaction	List-$II$ Reagents
$A$. Hoffmann Degradation	$I$. Conc. $KOH, \Delta$
$B$. Clemmensen reduction	$II$. $CHCl_3, NaOH / H_3O^{+}$
$C$. Cannizzaro reaction	$III$. $Br_2, NaOH$
$D$. Reimer-Tiemann reaction	$IV$. $Zn-Hg / HCl$

What is the product obtained when $m$-chlorobenzaldehyde is treated with a $50\% KOH$ solution?

Similar Questions

Match List-$I$ with List-$II$.

List-$I$ Reaction List-$II$ Reagents

$A$. Hoffmann Degradation $I$. Conc. $KOH, \Delta$

$B$. Clemmensen reduction $II$. $CHCl_3, NaOH / H_3O^{+}$

$C$. Cannizzaro reaction $III$. $Br_2, NaOH$

$D$. Reimer-Tiemann reaction $IV$. $Zn-Hg / HCl$

The product $(A)$ is:

Acetal or ketal is:

Tischenko reaction is a modification of

Consider the following reaction. The structure of the main product will be

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