HCHO + CH_3CHO xrightarrow[Heat]{dil. NaOH} A | vedclass

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(A) $1$. The reaction of $HCHO$ and $CH_3CHO$ with $dil. NaOH$ is a cross-aldol condensation. Since $HCHO$ has no $\alpha$-hydrogen,it acts as the ele

Vedclass · Accepted Answer

$CH_2=CH-CH(OH)-COOH$

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(A) $1$. The reaction of $HCHO$ and $CH_3CHO$ with $dil. NaOH$ is a cross-aldol condensation. Since $HCHO$ has no $\alpha$-hydrogen,it acts as the electrophile,and $CH_3CHO$ acts as the nucleophile. The product $A$ is $CH_2=CH-CHO$ (after dehydration of the aldol product $HO-CH_2-CH_2-CHO$).$2$. The reaction of $A$ $(CH_2=CH-CHO)$ with $HCN$ followed by hydrolysis $(H_3O^+)$ is a nucleophilic addition to the carbonyl group followed by hydrolysis of the nitrile group to a carboxylic acid.$3$. The addition of $HCN$ to $CH_2=CH-CHO$ gives $CH_2=CH-CH(OH)CN$.$4$. Hydrolysis of $CH_2=CH-CH(OH)CN$ gives $CH_2=CH-CH(OH)COOH$.

$HCHO + CH_3CHO$ $\xrightarrow[Heat]{dil. NaOH} A$ $\xrightarrow{HCN, H_3O^+} B$. What is the formula of $B$ in this reaction?

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