In the following reaction,{C_2H_5}O{C_2H_5} + | vedclass

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(A) The reaction of diethyl ether with excess $HI$ is a cleavage reaction.${C_2H_5}O{C_2H_5} + 2HI \rightarrow 2{C_2H_5}I + {H_2}O$Further reduction o

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Ethane

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(A) The reaction of diethyl ether with excess $HI$ is a cleavage reaction.${C_2H_5}O{C_2H_5} + 2HI \rightarrow 2{C_2H_5}I + {H_2}O$Further reduction of ethyl iodide with $HI$ (acting as a reducing agent) gives ethane:${C_2H_5}I + HI \rightarrow {C_2H_6} + I_2$Combining these steps,the overall reaction is:${C_2H_5}O{C_2H_5} + 4[H] \xrightarrow{HI} 2{C_2H_6} + {H_2}O$Therefore,$X$ is ${C_2H_6}$ (Ethane).

In the following reaction,
${C_2H_5}O{C_2H_5} + 4[H] \xrightarrow{HI} 2X + {H_2}O$
What is $X$ in this reaction?

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In the following reaction,${C_2H_5}O{C_2H_5} + 4[H] \xrightarrow{HI} 2X + {H_2}O$What is $X$ in this reaction?