(A) Ethylene glycol $(HOCH_2-CH_2OH)$ undergoes oxidation when treated with strong oxidizing agents like acidified $KMnO_4$.The reaction proceeds as f

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(A) Ethylene glycol $(HOCH_2-CH_2OH)$ undergoes oxidation when treated with strong oxidizing agents like acidified $KMnO_4$.The reaction proceeds as follows:$HOCH_2-CH_2OH + 2[O] \xrightarrow{H^+/KMnO_4} HOOC-COOH + 2H_2O$The final product obtained is oxalic acid $(HOOC-COOH)$.