The wavelength of light coming from a star is | vedclass

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Question

(A) According to the Doppler effect for light,the fractional change in wavelength is given by $\frac{\Delta \lambda}{\lambda} = \frac{v}{c}$,where $v$

Vedclass · Accepted Answer

Moving away with a velocity of $1.2 	imes 10^6 \ m/s$.

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(A) According to the Doppler effect for light,the fractional change in wavelength is given by $\frac{\Delta \lambda}{\lambda} = \frac{v}{c}$,where $v$ is the relative velocity of the source and $c$ is the speed of light $(3 	imes 10^8 \ m/s)$.Since the wavelength increases (redshift),the star is moving away from the observer.Given $\frac{\Delta \lambda}{\lambda} = 0.4\% = \frac{0.4}{100} = 0.004$.Substituting the values: $0.004 = \frac{v}{3 	imes 10^8 \ m/s}$.$v = 0.004 	imes 3 	imes 10^8 \ m/s = 1.2 	imes 10^6 \ m/s$.Thus,the star is moving away with a velocity of $1.2 	imes 10^6 \ m/s$.

The wavelength of light coming from a star is observed to increase by $0.4\%$. What is the velocity of the star?

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