Two waves have intensities x and y. If the ti | vedclass

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Question

(A) The relationship between time difference $(\Delta t)$ and phase difference $(\phi)$ is given by $\phi = \frac{2\pi}{T} 	imes \Delta t$.
Given $\

Vedclass · Accepted Answer

$(\sqrt{x} - \sqrt{y})^2$

Vedclass · Answer

(A) The relationship between time difference $(\Delta t)$ and phase difference $(\phi)$ is given by $\phi = \frac{2\pi}{T} 	imes \Delta t$.
Given $\Delta t = \frac{3T}{2}$,we substitute this into the formula:
$\phi = \frac{2\pi}{T} 	imes \frac{3T}{2} = 3\pi$.
The resultant intensity $I_R$ of two waves with intensities $I_1 = x$ and $I_2 = y$ is given by $I_R = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos(\phi)$.
Substituting $\phi = 3\pi$ and $\cos(3\pi) = -1$:
$I_R = x + y + 2\sqrt{xy}(-1) = x + y - 2\sqrt{xy} = (\sqrt{x} - \sqrt{y})^2$.
Therefore,the correct resultant intensity is $(\sqrt{x} - \sqrt{y})^2$.

Two waves have intensities $x$ and $y$. If the time difference between them is $3T/2$,what is the resultant intensity?

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