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(C) Given: Height of object $O = 5 \, cm$,Radius of curvature $R = 20 \, cm$,Object distance $u = -1 \, m = -100 \, cm$.For a concave mirror,focal len

Vedclass · Accepted Answer

$0.55$

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(C) Given: Height of object $O = 5 \, cm$,Radius of curvature $R = 20 \, cm$,Object distance $u = -1 \, m = -100 \, cm$.For a concave mirror,focal length $f = -R/2 = -10 \, cm$.The magnification formula is given by $m = I/O = f/(f - u)$.Substituting the values: $I/5 = -10 / (-10 - (-100))$.$I/5 = -10 / (-10 + 100) = -10 / 90 = -1/9$.$I = -5/9 \, cm \approx -0.55 \, cm$.The magnitude of the height of the image is $0.55 \, cm$.

An object of height $5 \, cm$ is placed at a distance of $1 \, m$ from a concave mirror of radius of curvature $20 \, cm$. What will be the height of the image in $cm$?

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