Identify the logic gate represented by the gi | vedclass

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(D) The circuit consists of four $NOR$ gates $(G_1, G_2, G_3, G_4)$.$G_1$ and $G_2$ act as $NOT$ gates because their inputs are tied together. Thus,th

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$NAND$

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(D) The circuit consists of four $NOR$ gates $(G_1, G_2, G_3, G_4)$.$G_1$ and $G_2$ act as $NOT$ gates because their inputs are tied together. Thus,the outputs are $\bar{A}$ and $\bar{B}$ respectively.These are fed into $G_3$,which is a $NOR$ gate. Its output is $\overline{\bar{A} + \bar{B}} = \overline{\bar{A}} \cdot \overline{\bar{B}} = A \cdot B$ (by De Morgan's Law).This output is fed into $G_4$,which acts as a $NOT$ gate. Its output is $\overline{A \cdot B}$.Thus,the final output $Y = \overline{A \cdot B}$,which is the Boolean expression for a $NAND$ gate.

$A$	$B$	$Y$
$1$	$1$	$0$
$1$	$0$	$0$
$0$	$1$	$0$
$0$	$0$	$1$

Identify the logic gate represented by the given circuit.

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