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(A) Efficiency $\eta = \frac{P_{	ext{out}}}{P_{	ext{in}}} = \frac{V_s I_s}{V_p I_p}$.Given: $\eta = 0.8$,$P_{	ext{in}} = 4 	imes 10^3 	ext{ W}$,$

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$40 	ext{ A}, 16 	ext{ A}$

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(A) Efficiency $\eta = \frac{P_{	ext{out}}}{P_{	ext{in}}} = \frac{V_s I_s}{V_p I_p}$.Given: $\eta = 0.8$,$P_{	ext{in}} = 4 	imes 10^3 	ext{ W}$,$V_p = 100 	ext{ V}$,$V_s = 200 	ext{ V}$.First,calculate the primary current $I_p$:$P_{	ext{in}} = V_p I_p \implies 4000 = 100 	imes I_p \implies I_p = 40 	ext{ A}$.Next,calculate the secondary current $I_s$ using efficiency:$0.8 = \frac{V_s I_s}{P_{	ext{in}}} \implies 0.8 = \frac{200 	imes I_s}{4000}$.$I_s = \frac{0.8 	imes 4000}{200} = 0.8 	imes 20 = 16 	ext{ A}$.Thus,the primary and secondary currents are $40 	ext{ A}$ and $16 	ext{ A}$ respectively.

$A$ transformer has an efficiency of $80 \%$. The input power to the primary coil is $4 \text{ kW}$ at a voltage of $100 \text{ V}$. If the secondary voltage is $200 \text{ V}$,what are the primary and secondary currents,respectively?

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