(A) The induced electromotive force $(e_2)$ in the secondary coil is given by the formula: $e_2 = M \frac{di_1}{dt}$.Since $e_2 = i_2 R_2$,we can equa

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(A) The induced electromotive force $(e_2)$ in the secondary coil is given by the formula: $e_2 = M \frac{di_1}{dt}$.Since $e_2 = i_2 R_2$,we can equate the two expressions: $i_2 R_2 = M \frac{di_1}{dt}$.Given values are: $M = 0.5 \ H$,$i_2 = 0.4 \ A$,and $R_2 = 5 \ \Omega$.Substituting these values into the equation: $0.4 \times 5 = 0.5 \times \frac{di_1}{dt}$.$2.0 = 0.5 \times \frac{di_1}{dt}$.Therefore,$\frac{di_1}{dt} = \frac{2.0}{0.5} = 4 \ A/s$.

Class 12 Physics Electromagnetic Induction Transformer

Difficult

In a transformer,the mutual inductance between the primary and secondary coils is $0.5 \ H$. The resistances of the primary and secondary coils are $20 \ \Omega$ and $5 \ \Omega$ respectively. To induce a current of $0.4 \ A$ in the secondary coil,what is the required rate of change of current in the primary coil in $A/s$?

A
$4$
B
$16$
C
$1.6$
D
$8$

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Class 12 Questions

Class 12

Physics Questions

Chapter

Electromagnetic Induction

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Transformer

$A$ transformer has $120$ turns in the primary coil and carries $5 \text{ A}$ current. Input power is $1 \text{ kW}$. To have $560 \text{ V}$ output, the number of turns in the secondary coil will be:

EasyMHT CET 2024

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$A$ power transformer is used to step up an alternating $e.m.f.$ of $220\,V$ to $11\,kV$ to transmit $4.4\,kW$ of power. If the primary coil has $1000$ turns,what is the current rating of the secondary (in $,A$)? Assume $100\%$ efficiency for the transformer.

Easy

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The turn ratio of a transformer is given as $2 : 3$. If the current through the primary coil is $3 \, A$,calculate the current through the load resistance (secondary coil). (in $, A$)

Easy

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$A$ transformer has an efficiency of $80 \%$ and works at $10 \ V$ and $4 \ kW$. If the secondary voltage is $240 \ V$, then the current in the secondary coil is: (in $A$)

DifficultJEE MAIN 2024

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$A$ transformer consists of $500$ turns in the primary coil and $10$ turns in the secondary coil with a load of $10\, \Omega$. Find the current in the primary coil when the voltage across the secondary coil is $50\, V$. (in $A$)

MediumAIIMS 2019

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$A$ transformer has $120$ turns in the primary coil and carries $5 \text{ A}$ current. Input power is $1 \text{ kW}$. To have $560 \text{ V}$ output, the number of turns in the secondary coil will be:

$A$ power transformer is used to step up an alternating $e.m.f.$ of $220\,V$ to $11\,kV$ to transmit $4.4\,kW$ of power. If the primary coil has $1000$ turns,what is the current rating of the secondary (in $,A$)? Assume $100\%$ efficiency for the transformer.

The turn ratio of a transformer is given as $2 : 3$. If the current through the primary coil is $3 \, A$,calculate the current through the load resistance (secondary coil). (in $, A$)

$A$ transformer has an efficiency of $80 \%$ and works at $10 \ V$ and $4 \ kW$. If the secondary voltage is $240 \ V$, then the current in the secondary coil is: (in $A$)

$A$ transformer consists of $500$ turns in the primary coil and $10$ turns in the secondary coil with a load of $10\, \Omega$. Find the current in the primary coil when the voltage across the secondary coil is $50\, V$. (in $A$)

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