The binding energy per nucleon for deuteron ( | vedclass

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(C) The nuclear fusion reaction is given by: $_1^2H + _1^2H 	o _2^4He + Q$.The total binding energy of a helium nucleus $(_2^4He)$ is $4 	imes 7 \,

Vedclass · Accepted Answer

$23.6$

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(C) The nuclear fusion reaction is given by: $_1^2H + _1^2H 	o _2^4He + Q$.The total binding energy of a helium nucleus $(_2^4He)$ is $4 	imes 7 \, MeV = 28 \, MeV$.The binding energy of one deuteron nucleus $(_1^2H)$ is $2 	imes 1.1 \, MeV = 2.2 \, MeV$.Since there are two deuteron nuclei in the reactants,the total binding energy of the reactants is $2 	imes 2.2 \, MeV = 4.4 \, MeV$.The energy released $Q$ is the difference between the binding energy of the product and the total binding energy of the reactants:$Q = 28 \, MeV - 4.4 \, MeV = 23.6 \, MeV$.

The binding energy per nucleon for deuteron $(_1^2H)$ and helium $(_2^4He)$ nuclei are $1.1 \, MeV$ and $7 \, MeV$ respectively. Calculate the energy released in $MeV$ when two deuteron nuclei fuse to form a helium nucleus.

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