If the de Broglie wavelength of an electron i | vedclass

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Question

(B) The de Broglie wavelength is given by the formula $\lambda = \frac{h}{mv}$,where $h$ is Planck's constant $(6.6 	imes 10^{-34} \ J \cdot s)$,$m$

Vedclass · Accepted Answer

$1.4 	imes 10^3 \ m/s$

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(B) The de Broglie wavelength is given by the formula $\lambda = \frac{h}{mv}$,where $h$ is Planck's constant $(6.6 	imes 10^{-34} \ J \cdot s)$,$m$ is the mass of the electron $(9.1 	imes 10^{-31} \ kg)$,and $v$ is the velocity.Rearranging for velocity: $v = \frac{h}{m\lambda}$.Substituting the given values: $v = \frac{6.6 	imes 10^{-34}}{9.1 	imes 10^{-31} 	imes 5200 	imes 10^{-10}}$.Calculating the denominator: $9.1 	imes 5200 	imes 10^{-41} \approx 4.732 	imes 10^{-37}$.Thus,$v = \frac{6.6 	imes 10^{-34}}{4.732 	imes 10^{-37}} \approx 1.394 	imes 10^3 \ m/s$.Rounding to the nearest option,$v \approx 1.4 	imes 10^3 \ m/s$.

If the de Broglie wavelength of an electron is $5200 \ \mathring{A}$,what is its velocity?

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