The wavelength of an electron and a photon ar | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For an electron,the de Broglie wavelength is given by $\lambda = \frac{h}{p}$,which implies $p = \frac{h}{\lambda}$.For a photon,the energy is giv

Vedclass · Accepted Answer

$3.33 	imes 10^{-9}$

Vedclass · Answer

(B) For an electron,the de Broglie wavelength is given by $\lambda = \frac{h}{p}$,which implies $p = \frac{h}{\lambda}$.For a photon,the energy is given by $E = \frac{hc}{\lambda}$.We are asked to find the ratio $p/E$.Substituting the expressions for $p$ and $E$:$\frac{p}{E} = \frac{h/\lambda}{hc/\lambda} = \frac{h}{\lambda} 	imes \frac{\lambda}{hc} = \frac{1}{c}$.Given the speed of light $c = 3 	imes 10^8 \ m/s$,we have:$\frac{p}{E} = \frac{1}{3 	imes 10^8} = 0.333 	imes 10^{-8} = 3.33 	imes 10^{-9} \ s/m$.

The wavelength of an electron and a photon are equal. If the energy of the photon is $E$ and the momentum of the electron is $p$,what is the value of $p/E$?

Similar Questions

$A$ laser produces a beam of light of frequency $5 \times 10^{14} \,Hz$ with an output power of $33 \,mW$. The average number of photons emitted by the laser per second is (Planck's constant $h = 6.6 \times 10^{-34} \,J \,s$)

According to the corpuscular theory of light,the different colours of light are due to

If a photon has velocity $c$ and frequency $\nu$,then which of the following represents its wavelength?

Find the number of photons emitted per second by a $100 \ W$ bulb emitting light of wavelength $540 \ nm$. (Given: $h = 6 \times 10^{-34} \ J \cdot s$)

Assertion: Mass of a moving photon varies inversely as the wavelength.
Reason: Energy of the particle $= \text{mass} \times (\text{speed of light})^2$

Vedclass Test Series

Exam Paper Generator

Online Exam Module