The coercivity of a small magnet is 4 times 1 | vedclass

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(C) The magnetic field intensity $H$ required to demagnetize a material is equal to its coercivity.For a solenoid,the magnetic field intensity is give

Vedclass · Accepted Answer

$8$

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(C) The magnetic field intensity $H$ required to demagnetize a material is equal to its coercivity.For a solenoid,the magnetic field intensity is given by the formula $H = n \cdot i$,where $n$ is the number of turns per unit length and $i$ is the current.The number of turns per unit length $n$ is calculated as $n = \frac{N}{L} = \frac{500 	ext{ turns}}{1 	ext{ m}} = 500 	ext{ m}^{-1}$.Given $H = 4 	imes 10^3 \ A/m$,we substitute the values into the formula:$4 	imes 10^3 = 500 	imes i$$i = \frac{4000}{500} = 8 \ A$.Therefore,the required current is $8 \ A$.

The coercivity of a small magnet is $4 \times 10^3 \ A/m$. It is placed inside a solenoid of length $1 \ m$ having $500$ turns to demagnetize it. The current that must be passed through the solenoid is .......... $A$.

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