Two magnetic poles have a pole strength of 0. | vedclass

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(C) The pole strength $m = 0.01 \, A \cdot m$. The distance between the poles is $d = 0.1 \, m$. The midpoint is at a distance $r = d/2 = 0.05 \, m$ f

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$8 	imes 10^{-7} \, T$

Vedclass · Answer

(C) The pole strength $m = 0.01 \, A \cdot m$. The distance between the poles is $d = 0.1 \, m$. The midpoint is at a distance $r = d/2 = 0.05 \, m$ from each pole.At the midpoint,the magnetic field due to the North pole $(B_N)$ is directed away from it,and the magnetic field due to the South pole $(B_S)$ is directed towards it. Both fields point in the same direction.The magnitude of the magnetic field due to a single pole is given by $B = \frac{\mu_0}{4\pi} \frac{m}{r^2}$.$B_N = B_S = 10^{-7} 	imes \frac{0.01}{(0.05)^2} = 10^{-7} 	imes \frac{0.01}{0.0025} = 10^{-7} 	imes 4 = 4 	imes 10^{-7} \, T$.The net magnetic field $B_{net} = B_N + B_S = 4 	imes 10^{-7} + 4 	imes 10^{-7} = 8 	imes 10^{-7} \, T$.

Two magnetic poles have a pole strength of $0.01 \, A \cdot m$ each and are separated by a distance of $0.1 \, m$. What is the magnetic field at the midpoint between the two poles?

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