What is the equivalent resistance between poi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To find the equivalent resistance between $A$ and $B$,we simplify the circuit step-by-step.$1$. The two resistors of resistance $r$ in the middle

Vedclass · Accepted Answer

$\frac{8}{7}r$

Vedclass · Answer

(D) To find the equivalent resistance between $A$ and $B$,we simplify the circuit step-by-step.$1$. The two resistors of resistance $r$ in the middle branch are in series,giving $r + r = 2r$.$2$. This $2r$ is in parallel with the top resistor $r$,giving equivalent resistance $R_p = \frac{r \cdot 2r}{r + 2r} = \frac{2}{3}r$.$3$. Now,the circuit consists of the left branch (resistance $r$),the right branch (resistance $r$),the top branch (resistance $\frac{2}{3}r$),and the bottom branch (resistance $r + r = 2r$ between $A$ and $B$).$4$. Simplifying further as shown in the diagram,the total resistance between $A$ and $B$ is the parallel combination of the upper path (total resistance $r + \frac{2}{3}r + r = \frac{8}{3}r$) and the lower path (total resistance $2r$).$5$. $R_{eq} = \frac{(\frac{8}{3}r) \cdot (2r)}{\frac{8}{3}r + 2r} = \frac{\frac{16}{3}r^2}{\frac{14}{3}r} = \frac{16}{14}r = \frac{8}{7}r$.

What is the equivalent resistance between points $A$ and $B$ in the given circuit?

Similar Questions

The total power dissipated in watts in the circuit shown is ............. $W$.

$3$ identical bulbs are connected in series and these together dissipate a power $P$. If now the bulbs are connected in parallel,then the power dissipated will be

$A$ student has $10$ resistors of resistance $r$. The minimum resistance made by him from given resistors is

Three resistances of equal values are arranged in four different configurations as shown below. Power dissipation in the increasing order is

$A$ wire of resistance $R$ is bent to form a square $ABCD$ as shown in the figure. The effective resistance between $E$ and $C$ is ( $E$ is the mid-point of arm $CD$ ).

Vedclass Test Series

Exam Paper Generator

Online Exam Module