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(C) The circuit can be analyzed by identifying the Wheatstone bridge structure. Looking at the circuit,the central part forms a balanced Wheatstone br

Vedclass · Accepted Answer

$30 \,\Omega$

Vedclass · Answer

(C) The circuit can be analyzed by identifying the Wheatstone bridge structure. Looking at the circuit,the central part forms a balanced Wheatstone bridge because the ratio of resistors in the arms is equal $(10/10 = 10/10)$. In a balanced Wheatstone bridge,no current flows through the central resistor,so it can be removed. After removing the central resistor,the circuit simplifies to a series combination of three $10 \,\Omega$ resistors between points $A$ and $D$. Thus,the equivalent resistance is $R_{eq} = 10 \,\Omega + 10 \,\Omega + 10 \,\Omega = 30 \,\Omega$.

What is the equivalent resistance between $A$ and $D$ in the given circuit? (All resistors are $10 \,\Omega$)

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