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Question

(A) The standard equation for simple harmonic motion is given by $y = a \sin (\omega t + \phi)$.Comparing this with the given equation $y = 0.30 \sin

Vedclass · Accepted Answer

$35 \, Hz, \, 66 \, m/s$

Vedclass · Answer

(A) The standard equation for simple harmonic motion is given by $y = a \sin (\omega t + \phi)$.Comparing this with the given equation $y = 0.30 \sin (220 \, t + 0.64)$,we get amplitude $a = 0.30 \, m$ and angular frequency $\omega = 220 \, rad/s$.The frequency $n$ is calculated as $n = \frac{\omega}{2\pi} = \frac{220}{2 	imes 3.14159} \approx 35.01 \, Hz \approx 35 \, Hz$.The maximum velocity $v_{max}$ is given by $v_{max} = a \omega$.Substituting the values,$v_{max} = 0.30 	imes 220 = 66 \, m/s$.Thus,the frequency is $35 \, Hz$ and the maximum velocity is $66 \, m/s$.

For a simple harmonic motion represented by the equation $y = 0.30 \sin (220 \, t + 0.64) \ m$,what are the frequency and maximum velocity,respectively?

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